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sort CA's by count, not name

This commit is contained in:
Hubert Kario 2016-09-06 14:08:06 +02:00
parent 74dd82e8ad
commit 0120fff9bc

View File

@ -19,6 +19,7 @@ import sys
from collections import defaultdict from collections import defaultdict
import os import os
from OpenSSL import crypto from OpenSSL import crypto
from operator import itemgetter
invocations = defaultdict(int) invocations = defaultdict(int)
@ -321,12 +322,12 @@ for stat in sorted(effective_security):
print("\nRoot CAs Count Percent") print("\nRoot CAs Count Percent")
print("---------------------------------------------+---------+-------") print("---------------------------------------------+---------+-------")
for stat in sorted(root_CA): for stat, val in sorted(root_CA.items(), key=itemgetter(1), reverse=True):
percent = round(root_CA[stat] / total * 100, 4) percent = round(val / total * 100, 4)
sys.stdout.write(stat.ljust(45)[0:45] + " " + str(root_CA[stat]).ljust(10) + str(percent).ljust(4) + "\n") sys.stdout.write(stat.ljust(45)[0:45] + " " + str(val).ljust(10) + str(percent).ljust(4) + "\n")
print("\nIntermediate CA Count Percent") print("\nIntermediate CA Count Percent")
print("---------------------------------------------+---------+-------") print("---------------------------------------------+---------+-------")
for stat in sorted(intermediate_CA): for stat, val in sorted(intermediate_CA.items(), key=itemgetter(1), reverse=True):
percent = round(intermediate_CA[stat] / total * 100, 4) percent = round(val / total * 100, 4)
sys.stdout.write(stat.ljust(45)[0:45] + " " + str(intermediate_CA[stat]).ljust(10) + str(percent).ljust(4) + "\n") sys.stdout.write(stat.ljust(45)[0:45] + " " + str(val).ljust(10) + str(percent).ljust(4) + "\n")